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472 series/series.33.p




Description

This article is from the Puzzles FAQ, by Chris Cole chris@questrel.questrel.com and Matthew Daly mwdaly@pobox.com with numerous contributions by others.

472 series/series.33.p


2 12 360 75600

series/series.33.s

2         = 2^1
12        = 2^2 * 3^1
360       = 2^3 * 3^2 * 5^1
75600     = 2^4 * 3^3 * 5^2 * 7^1
174636000 = 2^5 * 3^4 * 5^3 * 7^2 * 11^1

 

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