This article is from the Puzzles FAQ, by Chris Cole email@example.com and Matthew Daly firstname.lastname@example.org with numerous contributions by others.
What is the maximum overhang you can create with an infinite supply of bricks?
You can create an infinite overhang.
Let us reverse the problem: how far can brick 1 be from brick 0?
Let us assume that the brick is of length 1.
To determine the place of the center of mass a(n): a(1)=1/2 a(n)=1/n[(n-1)*a(n-1)+[a(n-1)+1/2]]=a(n-1)+1/(2n) Thus n 1 n 1 a(n)=Sum -- = 1/2 Sum - = 1/2 H(n) m=1 2m m=1 m Needless to say the limit for n->oo of half the Harmonic series is oo.