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33 analysis/e.and.pi.p |
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33 analysis/e.and.pi.p |
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This article is from the Puzzles FAQ, by Chris Cole chris@questrel.questrel.com and Matthew Daly mwdaly@pobox.com with numerous contributions by others.
Without finding their numerical values, which is greater, e^(pi) or (pi)^e?
analysis/e.and.pi.s
e^(pi). Put x = pi/e - 1 in the inequality e^x > 1+x (x>0).
Continue to:
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